Respuesta :
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[tex] \tt↠(y^2+6)(−2y^2+7)[/tex]
[tex]\tt↠(-2y^2+7)y^2+6(-2y^2+7)[/tex]
[tex]\tt↠-2y^4+7y^2+6(−2y^2+7)[/tex]
[tex]\tt↠-2y^4+7y^2-12y^2+42[/tex]
[tex]\tt↠-2y^4-5y²+42[/tex]
Answer:
-2y⁴ - 5y² + 42
Step-by-step explanation:
[tex](y^2 + 6)(-2y^2 + 7)[/tex]
[tex]\mathrm{Apply\:FOIL\:method}:\quad \left(a+b\right)\left(c+d\right)=ac+ad+bc+bd[/tex]
Here First terms are
[tex]y^2 \textrm{ and } -2y^2\\(y^2)(-2y^2) = -2y^4[/tex]
Outer terms are y² and 7 ==> (y²)(7) = 7y²
Inner terms are 6 and -2y² ==> 6(-2y²) = -12y²
Last terms are 6 and 7 ==> 6.7 = 42
So result is obtained by adding all these terms
-2y⁴ + 7y² - 12² + 42 ==> -2y⁴ - 5y² + 42