[tex]\huge\text{Hey there!}[/tex]
[tex]\huge\textbf{First thing, let's get the formula for}\\\huge\textbf{the regular pentagon/polygon.}[/tex]
[tex]\mathbf{\dfrac{1}{2}\times \boxed{a}pothem\times\boxed{p}erimeter = {\boxed{a}rea}}[/tex]
[tex]\huge\textbf{Or we could simply say....}[/tex]
[tex]\mathbf{\dfrac{\boxed{n}umber\ of\ sides\ you\ have \times \boxed{s}ide \ length\ on\ one\ side\times \boxed{a}pothem}{2} = \boxed{a}rea}[/tex]
[tex]\huge\textbf{Let's plug the pieces to the equation,}\\\huge\textbf{since we have that information out the}\\\huge\textbf{way.}[/tex]
[tex]\bullet\mathbf{\ Number\ of\ sides \rightarrow \boxed{\bf 5}}[/tex]
[tex]\bullet\mathbf{\ Side\ length\ of\ one\ side \rightarrow \boxed{\bf 6\ inches}}[/tex]
[tex]\bullet\mathbf{\ Apothem \rightarrow \boxed{\bf 4\ inches}}[/tex]
[tex]\huge\textbf{Making the equation for you:}[/tex]
[tex]\mathbf{\dfrac{5\times 6 \times 4}{2} = \boxed{a}rea}[/tex]
[tex]\huge\textbf{Solving for the result:}[/tex]
[tex]\mathbf{\dfrac{5\times 6 \times 4}{2} = \boxed{a}rea}[/tex]
[tex]\mathbf{\dfrac{30\times 4}{2} = \boxed{a}rea}[/tex]
[tex]\mathbf{\dfrac{120}{2} =\boxed{a}rea}[/tex]
[tex]\mathbf{\dfrac{120\div2}{2\div2} = \boxed{a}rea}[/tex]
[tex]\mathbf{\dfrac{60}{1} = \boxed{a}rea}[/tex]
[tex]\mathbf{60\div1 = \boxed{a}rea}[/tex]
[tex]\mathbf{60 = \boxed{a}rea}[/tex]
[tex]\huge\textbf{Met the result....}[/tex]
[tex]\huge\text{Thus, your answer should be: \boxed{\mathsf{60\ in^2}}}\huge\checkmark[/tex]
[tex]\huge\text{Good luck on your assingment \& enjoy your day!}[/tex]
~[tex]\frak{Amphitrite1040:)}[/tex]
