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tanweeleong195oxyqwp

Answer:

4Hz

Step-by-step explanation:

Standard form of a sine or cosine function,

y = acos(b(x+c))

where a is the amplitude, b is the value to find the period. and c is the phase shift.

Period = \frac{2\pi}{b}

From the equation given in the question,

[tex]y = 3cos(8\pi \: t + \frac{\pi}{2} ) \\ y = 3cos(8\pi(t + \frac{1}{16} )) \: \: (factorising \: 8\pi \: out)[/tex]

We can see:

Amplitude = 3,

Period = \frac{2\pi}{8\pi} = 1 / 4

Phase Shift = 1 / 16

Now we want to find the frequency.

Frequency = 1 / Period

= 1 / (1/4)

= 4Hz

BasketballEinstein

Answer:

[tex]\displaystyle 4[/tex]

Step-by-step explanation:

[tex]\displaystyle y = Acos(Bx - C) + D[/tex]

When working with a trigonometric equation like this, always remember the information below:

[tex]\displaystyle Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A|[/tex]

So, the first procedure is to find the period of this graph, and when calculated, you should arrive at this:

[tex]\displaystyle \boxed{\frac{1}{4}} = \frac{2}{8\pi}\pi[/tex]

You will then plug this into the frequency formula, [tex]\displaystyle T^{-1} = F.[/tex] Look below:

[tex]\displaystyle \frac{1}{4}^{-1} = F \\ \\ \boxed{4 = F}[/tex]

Therefore, the frequency of motion is four hertz.

I am delighted to assist you at any time.

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