163.1 KJ of heat flows into the gas.
As the pressure is constant, then it is a isobaric process.
In this process , Heat flows is [tex]Q=nC_{p}[/tex]ΔT
Work done is represented by W = PΔV= nRΔT
γ for monoatomic gas is [tex]\frac{5}{3}[/tex]
So, their ratio is
[tex]\frac{W}{Q}[/tex] = [tex]\frac{R}{C_{P} }[/tex] = R/γR/γ-1 = [tex]\frac{2}{5}[/tex] ….. (1)
Hence, Ratio of W and Q is 2/5
Now given,
Pressure = 233 kPa = 233000 Pa
ΔV= 0.76-0.48 = 0.28[tex]m^{3}[/tex]
So, W = PΔV = 233000 × 0.28 = 65240J
From equation (1)
[tex]\frac{65240}{Q} =\frac{2}{5}[/tex]
Q = 163100J or 163.1 KJ
As the value of Q is positive so, 163.1 KJ of heat flows into the gas.
Learn about first law of thermodynamics here https://brainly.com/question/15071682
#SPJ4
