Answer:
[tex](x+3.2)^2+(y-2.1)^2=(4.3)^2[/tex]
Step-by-step explanation:
It is given that the center of the circle is (-3.2,2.1) and radius is 4.3.
Now, the equation of the circle with center (a,b) and the radius 'r' is represented as:
[tex](x-a)^2+(y-b)^2=r^2[/tex]
Now, the given center is (-3.2,2.1) and radius is 4.3, thus the equation of the circle becomes,:
[tex](x-(-3.2))^2+(y-2.1)^2=(4.3)^2[/tex]
[tex](x+3.2)^2+(y-2.1)^2=(4.3)^2[/tex]
Which is the required equation.
