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apologiabiology
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I am going to assume it is [tex] \frac{17-(6)(10)}{2+12} [/tex]
if it is then go to AAAAAAAAAA

if it is 17-(6)(10)/(2)+12 then go to BBBBBB





AAAAAAAAA
multiply first
[tex] \frac{17-(6)(10)}{2+12} [/tex]
[tex] \frac{17-60}{2+12} [/tex]
add and subtract since the top and botom are like parenthasees
[tex] \frac{-43}{24} [/tex]
dat is simplified


BBBBBBBBBBB

17-(6)(10)/(2)+12
multiply first
16-(60)/(2)+12
divide
16-30+12
add/subtract
-14+12
-2


if it is [tex] \frac{17-(6)(10)}{2+12} [/tex] then answer is -43/24

if it is 17-(6)(10)/(2)+12 then answer is -2

17 - (60/2) + 12 = 17 - 30 + 12 = -1

OR

17 - (6 x 5) + 12 = 17 - 30 + 12 = -1

Multiplication and division before addition and subtraction.

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