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During a construction project, heavy rain filled construction cones with water. The diameter of a cone is 12 in. and the height is 27 in. What is the volume of the water that filled one cone?

Respuesta :

volume of a cone = πr^2(h/3)
r=6
h=27

v = 
π(6^2)27/3
v = 
π (36)(9)

v=
π324 in. cubed
or 
v=1,017.36 in. cubed 

Answer:

the volume of the water that filled one cone is 1017.36 in³ approximately

Step-by-step explanation:

To find the volume of water that filled the a cone, we will use the formula;

V = π r² [tex]\frac{h}{3}[/tex]

π is a constant

r is the radius of the cone

h is the height

V = volume of the cone.

From the question given;

Diameter of a cone is 12 in., but radius id half of diameter, this implies r=d/2 = 12/2 = 6 in.

h = 27      and     π≈3.14

We can now proceed to insert the values into the formula;

V = π r² [tex]\frac{h}{3}[/tex]

   

     ≈ 3.14 × (6)² × [tex]\frac{27}{3}[/tex]

      ≈ 3.14×36×9

       ≈1017.36 in³

Therefore the volume of the water that filled one cone is 1017.36 in³ approximately