(05.01)The table shows the number of candies packed by Machine C. The equation shows the number of candies packed by Machine D. In both representations, x is a measure of the number of minutes and y is a measure of the number of candies packed. Machine C Candy Packing x (minutes) y (candies) 2 150 4 300 6 450 8 600 Machine D: y = 130x How many more candies could machine D pack than machine C in 11 minutes? 65 130 450 605

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itstrevcr itstrevcr · Answer 1 · 2018-05-19T11:22:19+02:00

The answer should be 605.

11 x 75 = 825
11 x 130 = 1430
1430 - 825 = 605

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keshavgandhi04 keshavgandhi04 · Answer 2 · 2022-01-24T14:17:47+01:00

To find the number of candies we need to calculate the given equation.

The Machine D packs 605 candies more than Machine C.

Given that,

By MachineC, Table shows the no. of candies packed.

TABLE

x(minute) y(candies)

2 150

4 300

6 450

8 600

By Machine D, equation shows the no. of candies packed.

[tex]y=130x[/tex]

At first we have to find how many candies packed by Machine C in a minute,

⇒[tex]150/2=75[/tex] candies per minute

So,The capacity of packing candies by Machine C is 75 per minute

Now, we will check for 11 minutes

⇒ [tex]11[/tex]×[tex]75[/tex][tex]=825[/tex] candies pack by machine C in 11 minutes

Calculate the number of candies in a minute by Machine D

[tex]y=130x[/tex]

[tex]y=130\times11\\ y=1430[/tex]

Now, we compare the capacity of MachineD by MachineC

⇒ [tex]1430-825=605[/tex]

Therefore, 605 more candies MachineD packs than MachineC in 11minutes

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