The velocity of the particle, in meters per second is 0.78 m/s
How to determine the velocity of the particle, in meters per second?
The position function is given as:
x(t) = e-(t - 3)2
Rewrite properly as
x(t) = e^-(t - 3)^2
Next, we differentiate the above function to determine the velocity function.
Using a graphing calculator, we have:
x'(t) = -2(t - 3) * e^-(t - 3)^2
At t = 2.5 s, we have:
x'(2.5) = -2(2.5 - 3) * e^-(2.5 - 3)^2
Evaluate
x'(2.5) = 0.78
Hence, the velocity of the particle, in meters per second is 0.78 m/s
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