A. The acceleration of the train is –0.68 m/s²
B. The stopping distance is 660 m
What is acceleration?
This is defined as the rate of change of velocity which time. It is expressed as
a = (v – u) / t
Where
- a is the acceleration
- v is the final velocity
- u is the initial velocity
- t is the time
A. How to determine the acceleration
- Initial velocity (u) = 30 m/s
- Final velocity (v) = 0 m/s
- Time (t) = 44 s
- Acceleration (a) =?
a = (v – u) / t
a = (0 – 30) / 44
a = –0.68 m/s²
B. How to determine the distance
- Initial velocity (u) = 30 m/s
- Final velocity (v) = 0 m/s
- Time (t) = 44 s
- Distance (s) =?
s = (v + u)t / 2
s = [(0 + 30) × 44]/ 2
s = (30 × 44) / 2
s = 1320 / 2
s = 660 m
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