A 0.900 kg block that is attached to a spring with spring constant 13.0 n/m when hit with the hammer has the amplitude of oscillation as 11.637 x 10^-3 cm.
When an object’s motion repeats in a predetermined cycle, it is said to be in periodic motion. The motion described here is an oscillation.
Spring and pendulum motion are two straightforward instances of oscillations, but there are numerous additional instances as well.
The fact that the item is in a stable equilibrium position is a key characteristic of periodic motion. A restorative force that is pointed in that direction as well. The application of force occurs in spring.
If x is the compression of the spring after it is hit,
1/2 k x² = 1/2 m v²
13 x² = .90 x (41 x 10⁻²)² 1681
x² = 116.37 x 10⁻⁴
x = 11.637 x 10^-5m
11.637 x 10^-3 cm
Amplitude of oscillation = 11.637 x 10^-3 cm
To know more about spring force visit:
https://brainly.com/question/14655680
#SPJ4