The average acceleration during the time interval 0 seconds to 10 seconds is [tex]\frac{V_{1}-V_{2} }{10}[/tex] unit per second per second.
As per the question statement, we are supposed to find out the average acceleration during the time interval 0 seconds to 10 seconds. But before solving this question we should be aware about what actually average acceleration is.
Average acceleration : [tex]\frac{change in velocity}{total time interval}[/tex]
Here in the question, we are not given information about velocity of the object hence we assume the initial and final velocities of the object to be [tex]V_{1}[/tex] and [tex]V_{2}[/tex] respectively, hence
Change in velocity = [tex]V_{1}-V_{2}[/tex]
Total time interval = [tex](10 - 0)sec=10sec[/tex]
Therefore by definition of average acceleration we get
[tex]A_{avg}[/tex][tex]= \frac{V_{1}-V_{2} }{10}[/tex] unit per sec per second
- Average acceleration: The rate at which the velocity changes is referred to as average acceleration. To determine the average acceleration of something, we divide the change in velocity by the amount of time that has passed.
To learn more about acceleration and kinetics, click on the link given below:
https://brainly.com/question/17352997
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