the solid oxide of generic metal m is added to 73 ml of water and reacts to produce a metal hydroxide solution that is 0.35 m in the resulting compound. the metal hydroxide solution then reacts with all of the 29 ml of 1.8 m hcl to form water and the metal salt. how many valence electrons must m have?

Neutralization is the process by which acids and bases salts and water. When reacting with water, neutralization leaves excess hydrogen or hydroxide ions in solution. The pH of a neutralized solution depends on the strength of the acid or base it contains. Mixing a strong acid and a strong base makes a neutral salt. Mixing a strong acid and a weak base produces an acid. Similarly, when a weak acid is mixed with a strong acid, the salts formed are basic. Neutralization is used in many applications.

For example, acid + base —-> salt + water i. e. NaOH (sodium hydroxide, base) + HCl (hydrochloric acid, acid) ——> NaCl (salt) + H2O (water)react to form

Reaction between metal oxide and H2O

Metal oxide + H2O --> M(OH)x

Reaction between metal oxide and HCl

M(OH)x + xH2O ---> MClx + xH2O

Volume = 29 mL

Molarity of HCl solution = 1.8 M

Moles of HCl = molarity * Volume

Moles of HCl = 1.8 M * 29 mL *10^-3 L/ 1 mL

Moles of HCl = 0.0522 mol

Volume = 73 mL

Molarity of M(OH)x = 0.35 M

Moles of M(OH)x = Volume * Concentration of M(OH)x

Moles of M(OH)x = 73 mL * 10^-3 L / 1mL *0.35 M

Moles of M(OH)2 = 0.02555 mol

x = moles of HCl / moles of M(OH)x

x = 0.0522 mol / 0.02555 mol

x = 2

Number of valance electron = x = 1

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