g a coin is tossed 10 times, recording whether it comes up heads or tails each time it is tossed. how many outcomes involve at least 8 heads?

Respuesta :

Using combination formula , total 987 ways or outcomes are possible /involve atleast 8 heads.

We have given that, a coin is tossed 10 times .

total possble outcomes = 2¹⁰ = 1024

here, the chances of occurrence of tail and heads and equal so, this is independent event .

we want to calculate total numbers of possble wats atleast 8 heads occurs .

At least 8 heads means exactly two toss gives Tail as a result.

here we count sequences with exactly 8 heads, and also count sequences with more than three heads. We could compute this by equivalent, by subtracting from 1025 the number of sequences with no head, only one head, and only 2 heads

= 1024 - ⁸C₀ ( + ⁸C₁ + ⁸C₂ )

= 1024 - ( 1+8+28) = 1024 - 37

= 987

Hence , 987 outcomes involve atleast 8 heads.

To learn more about Combination formula, refer:

https://brainly.com/question/4658834

#SPJ4