Image should be located behind the mirror at a distance of 200/9 cm,
the image will be diminished and in the ratio of 4:9 compared to the original.
The given object has following properties
Focal length = f = 40cm
The object is placed at a distance of 50 cm in front of the mirror ,hence the negative sign is used.
u = -50cm
Using mirror formula ,
1/f = 1/v + 1/u
1/40 = 1/v + 1/-50
1/v = 9/200
V = + 200/9
The + sign indicates that the image will be placed behind the mirror . i.e. , an imaginary image will be formed.
Magnification = v/u
= (200/9) /50
= 4/9
This means the image will be diminished and in the ratio of 4:9 compared to the given object.
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