The calculated answer is NpVs = NsVp=- 0.086A
utilizing the transformer formula, which, as shown, connects the coil's number of turns N, emf V, and produced current I;
where Ns/Np = Vs/Vp = Ip/Is;
The secondary and primary coils' respective turn counts are Ns and Np, respectively.
The relative emf in the secondary and primary coils is Vs and Vp.
The current in the secondary and primary coils, respectively, is and is
assuming Vp = 120V (input voltage), Np = 384 turns, and Vs = 9V (output voltage) Ns =?
Using the equation Ns/Np = Vs/Vp
Ns/384 = 9/120
multiplying by two
120Ns = 384×9
120Ns = 3456
Ns = 3456/120
Ns = 28.8
Ns = roughly 29 turns
9/120 = Ip/1.14
multiplied by two;
120Ip = 9×1.14
120Ip = 10.26
Ip = 10.26/120
Ip = 0.086A
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