a certain field is a rectangle with a perimeter of feet. the length is feet more than the width. find the width and length of the rectangular field.

Respuesta :

The length and width of the rectangular field is 316 ft and 133 ft respectively.

An algebraic equation is a mathematical statement that equalises two expressions. A variable, coefficients, and constants are common components of an algebraic equation. Also look into Algebraic Expressions. Equality is represented by equations or the equal sign.

It is balanced because both sides are equal in value. To avoid making an error that throws the equation out of balance, ensure that any change on one side is reciprocated on the other.

Given,

perimeter of rectangular field = 898 ft

let width be 'x'

then,

length = x+183

The perimeter of a rectangle is,

[tex]P = 2(length + width)\\\\898 = 2( ( x + 183 ) + x )\\\\898 = 2(2x+183)\\\\898 = 4x + 366\\\\4x = 898 - 366\\\\4x = 532\\\\x=\frac{532}{4}\\\\x=133[/tex]

Thus, the width is 133 ft and length is (133+183)=316 ft.

To learn more about algebraic equations refer herre

https://brainly.com/question/27990625

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Your question is incomplete, here is the complete question.

A certain field is a rectangle with a perimeter of 898 ft. The length is 183 ft more then the width. Find the width and length of the rectangular field?

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