2.95 l of n2(g) is mixed with 3.84 l of h2(g) and reacts with 100% yield. what volume of nh3(g) is produced? assume all gases are at the same temperature and pressure.

Respuesta :

Volume of nh3(g) is produced is 2.56L

N2(g)+3H2(g)→2NH3(g)

As per the reaction stochiometry we see that the gaseous ractants and products are in the following mole ratio 1:3:2 So ratio of their volume will also follow same ratio.

Hence to maintain that ratio the

2.95L N2(g) will react with 8.85L H2(g) to form theoretically 2⋅2.95L=5.90L NH3(g)

But the volume of H2(g) will fall short then. So hydrogen given will be fully consumed and the yeild of NH3(g) to be calculated on the consumption of of available H2(g) i.e. 3.84L

So theoretical yeild of NH3(g) will be =(2/3)×3.84L≈2.56L

Stoichiometry:

Stoichiometry is the area of ​​chemistry that involves using the relationships between reactants and/or products in a chemical reaction to determine quantitative data of interest. In Greek, stoicane means element and metron means measure, so stoichiometry literally means measure of elements.

Learn more about Stoichiometry here:

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