To decrease the area of the circle by $48\pi$, we need to decrease the radius by a factor of $\sqrt{48\pi}$.
Since the original radius of the circle was 8, the radius must be decreased to
Therefore, to decrease the area of the circle by $48\pi$, the radius must be decreased by a factor of about 1.1547.
This means that the radius must be decreased by a number that is about 1.1547 times smaller than the original radius of 8, or by about $8 \times (1 - 1.1547) = -0.6158$.
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