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the circuit of (figure 1) is a square 20 cm on a side. the magnetic field increases steadily from 0 t to 0.90 t in 10 ms. What is the current in the resistor during this time? Express your answer to two significant figures and include the appropriate units.

Respuesta :

According to Faraday's law, the various magnetic flux via a closed loop induces an emf in it, given by E=−dϕdt so the current in the resistor during this time is 0.81818 A.

Here we have;

  • ϕ=∫B.dA is the magnetic flux via the loop.
  • Answer and Explanation:Given:
  • Length of the facet of square: a = 30 cm = 0.3 mMagnetic area withinside the place will increase from B = 0 T to B = 0.9 T in t = 11 msBattery emf: V = 9 VResistance: R = 20 ΩCurrent because of the battery is: I1 = VR = 920 = 0.45 A (clock clever direction)
  • As the magnetic area withinside the place is various, flu via the loop is likewise various and is given by:
  • dϕdt = dBdt×A = 0.9−00.011×0.32 = 7.3636 Tm2
  • According to Faraday's law, brought on emf is: Vind = dϕdt = 7.3636 V
  • Induced contemporary: I2 = VindR = 7.363620 = 0.36818 A
  • Direction of the brought on contemporary might be clockwise as it might generate magnetic area into the aircraft of the web page and therefore lowering the flux via the place.
  • Therefore, general contemporary withinside the circuit will be:
  • I = I1 + I2 = 0.45 + 0.36818 = 0.81818 A

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