the base of a solid is a circular disk with radius 3. Therefore, the volume of the solid is 27π.
The volume of a solid is determined using the formula V = πr²h, where r is the radius of the base and h is the height of the solid. In this problem, the base is a circular disk with radius 3, and the cross-sections are isosceles right triangles with hypotenuse lying along the base. Since the cross-sections are isosceles right triangles, the height of each triangle is equal to the radius of the base, which is 3. Therefore, the height of the solid is also 3. Substituting these values into the formula gives V = π(3)²(3), which simplifies to V = 27π.
Therefore, the volume of the solid is:
V = πr²h
V = π(3)²(3)
V = 27π
Therefore, the volume of the solid is 27π.
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