a string and allowed to revolve in a circle
of radius 1.7 m on a frictionless horizontal
surface. The other end of the string passes
through a hole in the center of the surface,
and a mass of 1.5 kg is tied to it, as shown.
The suspended mass remains in equilibrium
while the puck revolves on the surface.
0.029 kg
1.7 m
1.5 kg
What is the magnitude of the force that
maintains circular motion acting on the puck?
The acceleration due to gravity is 9.81 m/s?.
Answer in units of N.
part 2 of 2
What is the linear speed of the puck?
Answer in units of m/s.

Question

10-12-2022
Physics

contestada

a string and allowed to revolve in a circle
of radius 1.7 m on a frictionless horizontal
surface. The other end of the string passes
through a hole in the center of the surface,
and a mass of 1.5 kg is tied to it, as shown.
The suspended mass remains in equilibrium
while the puck revolves on the surface.
0.029 kg
1.7 m
1.5 kg
What is the magnitude of the force that
maintains circular motion acting on the puck?
The acceleration due to gravity is 9.81 m/s?.
Answer in units of N.
part 2 of 2
What is the linear speed of the puck?
Answer in units of m/s.

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DimahiS DimahiS · Answer 1 · 2022-12-16T01:14:53+01:00

The magnitude of the force that maintains circular motion acting on the puck is 15.68 Newtons and the linear speed of the puck is 30.854 m/s.

Uniform circular motion is the motion in a circle at constant speed and Instantaneous velocity is always tangent to the circle. The acceleration, called the centripetal acceleration, points toward the center of the circle.

For an object to be in uniform circular motion, Newton’s 2 nd law requires a net force acting on it. This net force is called centripetal force. Physically, the centripetal force can be the tension in a string, the gravity on a satellite, the normal force of a ring, etc.

Don’t count the centripetal force as an additional force in the free-body-diagram.. It refers to the required net force for circular motion.A centrifuge works by spinning very fast. An object in the tube requires a large centripetal force. When the liquid can’t provide such a large force, the object will move (sink) to the end of the tube.

we have,

Force = mg = 1.6 x 9.8 = 15.68 Newtons

now Force = F = m'v^2/R

15.68 = 0.028 x v^2/1.7

Speed = v = 30.854 m/s

To know more about circular motion here

https://brainly.com/question/13592526

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