An organic compound contains 20.0 % Carbon, 6.66% Hydrogen, 47.33% Nitrogen and the rest was Oxygen. Its molar mass is 60 gm. The molecular formula of the compound is? (A)
C
H
4
N
2
O
(B)
C
H
2
N
O
2
(C)
C
2
H
6
N
O
(D)
C
H
18
N
O

After dividing the actual yield produced in the lab by the predicted theoretical yield, multiply the result by 100 to determine the yield percentage.

How do you figure out the recovery percentage?

Percent recovery is calculated as the difference between what you actually gathered and what you were expected to collect. Consider that after recrystallization, you obtained 7.0 g of dry pure material from 10.0 g of impure material. Your recovery rate is then 70% (7/10 x 100).

To know more about molecular formula visit:-

https://brainly.com/question/28647690

#SPJ4

An organic compound contains 20.0 % Carbon, 6.66% Hydrogen, 47.33% Nitrogen and the rest was Oxygen. Its molar mass is 60 gm. The molecular formula of the compound is? (A) C H 4 N 2 O (B) C H 2 N O 2 (C) C 2 H 6 N O (D) C H 18 N O

Respuesta :

How is an organic molecule's percent yield calculated?

How do you figure out the recovery percentage?

Otras preguntas

An organic compound contains 20.0 % Carbon, 6.66% Hydrogen, 47.33% Nitrogen and the rest was Oxygen. Its molar mass is 60 gm. The molecular formula of the compound is? (A)
C
H
4
N
2
O
(B)
C
H
2
N
O
2
(C)
C
2
H
6
N
O
(D)
C
H
18
N
O