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The general equation for the combination is as shown below,
                                      
                 C(n,r) = n!/(r!(n-r)!)

Note that the symbol "!" means factorial. 

In our example, n = 5 and r = 0. Substituting the known values,
                   C(5,0) = 5!/(0!(5-0)!) = 1

The answer to this item is 1. 

Combination is the number of arrangements in the collection of the times in which the order of the combination does not repeats. The value of the given combination is 1.

Given information-

The given  set of the combination is,

[tex]C(5, 0)[/tex]

Combination

Combination is the number of arrangements in the collection of the times in which the order of the combination does not repeats.

The standard equation of the combination can be given as,

[tex]C(n,r)=\dfrac{n!}{r!(n-r)!} [/tex]

Here [tex]n[/tex] is the total number of the objects in the set and[tex]r[/tex]is the choosing the object from the set.

In the given problem the value of [tex]n[/tex] and [tex]r[/tex] is given as 5 and 0 respectively.

Put the values in the formula,

[tex]C(5,0)=\dfrac{5!}{0!(5-0)!} [/tex]

The value of the 0 factorial is one. Solve it further,

[tex]C(5,0)=\dfrac{5!}{5!} \\ C(5,0)=1[/tex]

Hence the value of the given combination is 1.

Learn more about the combination here;

https://brainly.com/question/11234257

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