Given △JKL, sin(38°) equals
cos(38°).
cos(52°).
tan(38°).
tan(52°).

By definition, we have to:
[tex] sin(x) = \frac{C.O}{h} [/tex]
[tex] cos(x) = \frac{C.A}{h} [/tex]
Where,
x: angle
C.O: opposite leg
C.A: adjacent leg
h: hypotenuse
Using the definitions we have that for sin (38 °):
[tex] sin(38) = \frac{KJ}{KL} [/tex]
Then, we have the following trigonometric relationship:
[tex] cos(52)= \frac{KJ}{KL} [/tex]
Therefore, it is true that:
Sin(38) = cos(52)
Answer:
Given △JKL, sin(38°) equals:
cos(52°).
The value of Sin(38°) is equal to Cos(52°).
[tex]Sin \theta=\dfrac{Perpendicular}{Hypotenuse}[/tex]
[tex]Cos \theta=\dfrac{Base}{Hypotenuse}[/tex]
[tex]Tan \theta=\dfrac{Perpendicular}{Base}[/tex]
where perpendicular is the side of the triangle which is opposite to the angle, and the hypotenuse is the longest side of the triangle which is opposite to the 90° angle.
Given to us
1. For ∠L
[tex]Sin (\angle L) = \dfrac{Perpendicular}{Hypotenuse}[/tex]
Substituting the values,
[tex]Sin (38^o) = \dfrac{KJ}{KL}[/tex]
Therefore, we need to find the value of another ratio that is equal to [tex]\dfrac{KJ}{KL}[/tex].
2. For ∠K
[tex]Cos (\angle K) = \dfrac{Base}{Hypotenuse}[/tex]
Substituting the values,
[tex]Cos (52^o) = \dfrac{KJ}{KL}[/tex]
Hence, the value of Sin(38°) is equal to Cos(52°).
Learn more about Trigonometric functions:
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