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If a platinum wire has a resistance of 15 Ω and is connected across the terminals of a 3.0 V flashlight battery, how much current is in the wire? 1.0 amps 5.0 amps 7.5 amps 0.20 amps

Respuesta :

R = 15 Ω
V = 3.0 V

I = V/R = 3.0/15 = 0.2 amps
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Answer:

0.2Amperes

Explanation:

According to ohms law which state that the current passing through a metallic conductor at constant temperature is directly proportional to the potential difference across its ends. Mathematically, V= IR where;

V is the potential difference measured in volts = 3.0V

I is the total current flowing in the circuit

R is the resistance = 15ohms

From the formula given

I = V/R

Substituting the given values in the formula to get I, we have;

I = 3/15

I = 0.2Amperes

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