Respuesta :
moles= molarity x liter
=0.2500 M x 0.500 L
= 0.1250 mol
mass C2H2O4 . 2H2O = 0.1250 mol x (126.068 g / 1 mol)
=15.76 g
=0.2500 M x 0.500 L
= 0.1250 mol
mass C2H2O4 . 2H2O = 0.1250 mol x (126.068 g / 1 mol)
=15.76 g
This question is incomplete.
The complete question is: Calculate the mass of oxalic acid dihydrate [tex]C_2H_6O_6.2H_2O[/tex] needed to prepare 500.0 mL of 0.2500 M oxalic acid solution.
Answer: 15.75 grams
Explanation:
Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.
[tex]Molarity=\frac{n\times 1000}{V_s}[/tex]
where,
Molarity = 0.2500 M
n= moles of solute = ?
[tex]V_s[/tex] = volume of solution in ml = 500.0 ml
[tex]0.2500=\frac{n\times 1000}{500.0}[/tex]
[tex]n=0.1250[/tex]
Mass of oxalic acid dihydrate = [tex]moles\times {\text {Molar Mass}}=0.1250\times 126.07g/mol=15.75g[/tex]
Therefore, the mass of oxalic acid dihydrate needed to prepare 500.0 ml is 15.75 grams
