What does the transformation f(x)↦f(-x) do to the graph of f(x)?
a) stretches it horizontally
b) reflects it across the y-axis
c) shrinks it horizontally
d) reflects it across the x-axis
e) Submit



Respuesta :

The function will simply get reflected about the y-axis.
Let's approach this through what we know. Since we know that the x values are mirrored, we know that the points in Quadrant I and IV will be reflected over to the negative side, Quadrants II and III, because they simply change in signs.

However, we also know that the function y-values do not change. This is because whatever the x values are don't change the range and y-values of an even function.

To be more specific, if we have an even function, we are most likely dealing with quadratics or variants/transformations of the quadratic function.

If we were to have 2, and -2, and we wanted to plug them into the equation:
[tex]y = x^{2} + C[/tex], the signs do not change the y-values of the function.
Hence, we know that it ONLY gets reflected across the y-axis.

The transformation f(x)↦f(-x) , the graph of f(x) reflects it across the y-axis

Option B

Given :

The transformation f(x) -> f(-x)

For example , lets take a point on f(x)

Let (x,y) be a point on f(x)

given f(x)- > f(-x) it means x is replaced by -x

f(x) is not multiplied with -1  so y value remains the same

(x,y) be a point on f(x) .

After transformation f(x)-> f(-x) , the point (x,y) ---> (-x,y)

When x is multiplied by -1 then there is a reflection across the y axis

So, the graph of f(x) reflects it across the y axis.

Learn more :  brainly.com/question/12845351