Respuesta :
By "f(x = 2x + 1" you likely meant "f(x) = 2x + 1."
The given interval is [2,5], and so the width of each interval is (5-2)/n, or (3/n). Since we are using right end points, the x value at the right endpoint of the kth rectangle is 2+k(3/n). Examples: if k=1, the value at the right endpoint is 2+1(3/n); if k=2, 2+2(3/n), and so on. If k=n, then the value at the right endpoint is 2+n(3/n), or 2+3=5, which agrees with the given interval [2,5].
Once again, the given function is f(x) = 2x + 1.
At x = 2+k(3/n), the value of the function is 2[2+k(3/n)] + 1 (Answer). Check: If k=n, x = 2 + n(3/n) = 2+3 + 5, and f(5)=2(5) + 1 = 11.
The given interval is [2,5], and so the width of each interval is (5-2)/n, or (3/n). Since we are using right end points, the x value at the right endpoint of the kth rectangle is 2+k(3/n). Examples: if k=1, the value at the right endpoint is 2+1(3/n); if k=2, 2+2(3/n), and so on. If k=n, then the value at the right endpoint is 2+n(3/n), or 2+3=5, which agrees with the given interval [2,5].
Once again, the given function is f(x) = 2x + 1.
At x = 2+k(3/n), the value of the function is 2[2+k(3/n)] + 1 (Answer). Check: If k=n, x = 2 + n(3/n) = 2+3 + 5, and f(5)=2(5) + 1 = 11.
The value of the function at the right endpoint of the kth rectangle is; f(5) = 11.
What is the value of the function at the right endpoint of the kth rectangle?
From the task content, it follows that the given interval is; [2, 5]. On this note it follows that the domain of the function is as defined and the domain value at the right endpoint of the kth rectangle corresponds to x= 5.
The value of the function is therefore; f(x) = 2(5) +1.
f(x) = 11.
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