Barbara knows that she will need to buy a new car in 3 years. The car will cost $15,000 by then. How much should she invest now at 7%, compounded quarterly, so that she will have enough to buy a new car?

Respuesta :

A=p (1+I/k)^tk

A future value 15000
I interest rate 0.07
K compounded quarterly 4
T time 3
p principle ?

15000=p (1+0.07/4)^(4×3)
Solve for p
P=15,000÷(1+0.07÷4)^(4×3)
p=12,180.87

She should invest [tex]\$ 12181.25[/tex] now at [tex]7\%[/tex], compounded quarterly, so that she have enough to buy a new car.

What  is Compound interest?

Compound interest is  an interest which is earned on the principal and the interest together over a given time period.

We have, for Compound interest,

Amount [tex]= P(1+\frac{R}{100} )^t[/tex]

Also,

Amount [tex]=[/tex] Principal + Interest

We have,

Amount [tex]= \$ 15000[/tex]

Rate of Interest [tex]=7 \%[/tex]

Time period [tex]= 3[/tex] years

As compounded quarterly, then

Rate [tex]= \frac{7}{4}\%[/tex]

Time [tex]=3*4=12[/tex] years

Now,

[tex]15000 = P(1+\frac{7}{400} )^{12}[/tex]

[tex]15000=P(1.2314)[/tex]

[tex]P= \$ 12181.25[/tex]

Hence, we can say that she should invest [tex]\$ 12181.25[/tex] now at [tex]7 \%[/tex], compounded quarterly, so that she have enough to buy a new car.

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