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The depreciating value of a semi-truck can be modeled by y = Ao(0.85)x, where y is the remaining value of the semi, x is the time in years, and it depreciates at 15% per year.



What is the value of the truck initially, Ao, and how would the graph change if the initial value was only $65,000?
$70,000, and the graph would have a y-intercept at 10,000
$75,000, and the graph would have a y-intercept at 65,000
$75,000, and the graph would fall at a slower rate to the right
$75,000, and the graph would fall at a faster rate to the right

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BlueSky06
I've answered this question before, my answer was:

y = Ao(0.85)x

B. $75,000, and the graph would have a y-intercept at 65,000

Based on the graph, when x = 0 ; y = 75,000

If the initial value will be 65,000 instead of 75,000, then the y-intercept is 65,000.

The rate of the same all throughout. It is still depreciating at 15% per year.
Ver imagen BlueSky06
it's B
i just took the math exam and it said got that question right

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