Respuesta :
S = 2(ab + bc + ac)
(S/2) = ab + bc + ac
(S/2) - ac = ab + bc
(S/2) - ac = b(a+c)
[(S/2) - ac] / (a+c) = b
b = [(S/2) - ac] / (a+c)
(S/2) = ab + bc + ac
(S/2) - ac = ab + bc
(S/2) - ac = b(a+c)
[(S/2) - ac] / (a+c) = b
b = [(S/2) - ac] / (a+c)