Respuesta :
The luminous flux will be "4.65×10³ lm".
Given;
Distance b/t source and light bulb,
- d = 4.1 m
Illuminance,
- E = 22 lx
The formula,
→ [tex]P = E\times 4 \pi d^2[/tex]
By substituting the values, we get
[tex]= 22\times 4 \pi\times (4.1)^2[/tex]
[tex]= 4647.3 \ lx \ m^2[/tex]
[tex]= 4.65\times 10^3 \ lm[/tex]
Thus the answer above is appropriate.
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