Answer:
0
No such point on graph.
Step-by-step explanation:
Given: [tex]y=2x^2-7x+7[/tex]
We are given quadratic equation. We need to find number of points where it cuts x-axis.
When graph cuts x-axis their y-value is 0
We will set the equation to 0 and solve for x
[tex]2x^2-7x+7=0[/tex]
Using quadratic formula.
[tex]x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]
where, a=2 , b=-7 , c=7
[tex]x=\dfrac{7\pm\sqrt{49-56}}{2(2)}[/tex]
[tex]x=\dfrac{7\pm \sqrt{-7}}{4}[/tex]
[tex]x=\dfrac{7\pm i\sqrt{7}}{4}[/tex]
The value of x is imaginary. So, y will not cut x-axis any any point.
Hence, No such point on graph which cut x-axis.
