contestada

The molar mass of NH3 is 17.03 g/mol. The molar mass of H2 is 2.0158 g/mol. In a particular reaction, 0.575 g of NH3 forms. What is the mass, in grams, of H2 that must have reacted, to the correct number of significant figures?

Respuesta :

Nirina7
the answer 
the general for of the equation of reaction is 
N2        +     3 H2 ------------   2NH3
1mol            3mole                2 mole
                    nH2                   nNH3
(nX means number of mole of X)

according to the law of proportion
3 / nH2  =  2 / nNH3  (E)

nNH3 = m NH3  / 17.03 , and m NH3 = 0.575 g
consequently nNH3 =  0.575 g  / 17.03 = 0.03 mol

by considering (E)  3 / nH2  =  2 / 0.03 = 66.66, and nH2  = 3 / 66.66 =0.045

finally we can write 

mH2 = nH2 x 2.0158 =0.045 x 2.0158 = 0.09 g
daegutownsuga

Answer:

0.102

Explanation:

Otras preguntas