Respuesta :
Answer:[tex]6.03705\times 10^{-11} m[/tex] is atomic radius of an oxygen.
Explanation:
The bond length of O-O bond = [tex]1.20741\times 10^{-10} m[/tex]
The atomic radius oxygen will be given by:
[tex]\frac{\text{Bond lenght}}{2}=\frac{1.20741\times 10^{-10} m}{2}=6.03705\times 10^{-11} m[/tex]
[tex]6.03705\times 10^{-11} m[/tex] is atomic radius of an oxygen.
