An airplane left Miami, FL. At the same time another plane left Santiago, Chile. The two planes flew toward each other at rates of 625 mph and 575 mph. If Miami and Santiago are 4200 miles apart, how long will it take until the planes pass each other?

To solve the above question we use the concept of relative speed.
The rates of the two planes are 625 mph and 575 mph.
Relative speed will be:
[speed of plane A]+[speed of plane B]
=625+575
=1,200 mph
Distance=4200 miles
Thus the time taken for them to meet will be:
Time=distance/speed
=4200/1200
=3.5 hours
We therefore conclude that the planes met after 3.5 hours

Answer Link

lhmarianateixeira lhmarianateixeira · Answer 2 · 2022-04-25T17:06:43+02:00

The planes pass each other in 3.5 hours.

Given the information that:

The rates of the two planes are 625 mph and 575 mph.
If Miami and Santiago are 4200 miles apart

What is relative speed?

The relative velocity will be given by subtracting the velocities, the largest minus the smallest. When two mobiles are in opposite directions, towards each other, the relative speed of approach will be given by the sum of the speeds of each one.

So the formula for relative speed will be:

[tex][speed \ of \ plane \ A]+[speed \ of \ plane \ B]\\=625+575\\=1,200 mph[/tex]

Thus the time taken for them to meet will be:

[tex]Time=distance/speed\\=4200/1200\\=3.5 hours[/tex]

See more about speed at brainly.com/question/7359669