In 5 years, Dad will be three times as old as his daughter Jill will be then. If the sum of their present ages is 50, how old are they now? If y + 5 is Jill's age five years from now, which of the following equations could be used to solve the problem?

Respuesta :

First, we know (D is dad, J is Jill) that D+J=50.
Second, in 5 years D will be 3 times as old so
(D+5)= 3*(J+5)
Moving on, if we know D+J=50 then D=(50-J) is true.Taking that relationship and substituting for D in the other equation, it becomes
50 - J + 5 = 3 * (J + 5)
Then, it becomes 
50 - J + 5 = (3 * J) + (3 * 5)
Then, 55 - J = (3 * J) + 15 
Then, 55 - 15 = (3 * J) + J
which becomes 40 = 4*J

Answer:

Dad's current age is 40 years and Jill's age is 10 years.

Step-by-step explanation:

Let Dad's current age be = x

Let Jill's current age be = y

The sum of their present ages = 50

We get : [tex]x+y=50[/tex]  or [tex]x=50-y[/tex]  

In 5 years, Dad will be three times as old as his daughter Jill will be then.

[tex]x+5=3(y+5)[/tex]

Putting the value of x here;

[tex]50-y+5=3y+15[/tex]

=> [tex]55-y=3y+15[/tex]

=> [tex]3y+y=55-15[/tex]

=> [tex]4y=40[/tex]

y = 10

And [tex]x=50-10[/tex]  

x = 40

Hence, dad's current age is 40 years and Jill's age is 10 years.