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If 3 L N2 and 3 LH2 are mixed and react according to the equation below, how many liters of unreacted gas remain? Assume temperature and pressure remain constant.
N2(g) + 3H2(g) → 2NH3(g)

Respuesta :

N₂ + 3H₂ → 3NH₃
1L    3L    (1:3 according to the reaction equation)

N₂ + 3H₂ → 3NH₃
3L    3L

3L - 1L = 2L
2 liters of unreacted gas (N₂) remain

"Assuming the temperature and pressure remain constant, 2L of unreacted gas remains or will remain".

What is leftover reactant (unreacted reactant)?

Excess reagents are reactants that are not consumed fully when a chemical reaction is complete. After a chemical reaction has reached equilibrium, the reactant(s) remain. The excess reagent is the reactant that is also referred as  "left over reactant" in a chemical reaction.

Ammonia (NH3) is a chemical substance formed by the reactions of nitrogen and hydrogen. Ammonia is generated through the interaction of N2 and H2 gas in a 1:3 ratio.

3L of nitrogen gas and 3L of hydrogen gas are mixed to react according to the balanced equation.

N₂ + 3H₂ → 3NH₃

1L    3L    (1:3 according to the reaction equation)

So, in nitrogen gas,

3L - 1L = 2L

2 liters of unreacted gas (N₂) remain.

Thus, 1 litre of nitrogen gas is enough to react with 3 litres of hydrogen gas to form ammonia.

Hence the correct answer is 2L of nitrogen gas.

Learn more about unreacted reactant here

https://brainly.com/question/21229218

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