The value of a if the quadratic function is written in the form
[tex]\rm y = a(x-h)^2 +k[/tex] given as follows
a = -3
Vertex of the parabola is the point where parabola passes its axis of symmetry it is generally denoted as (h,k).
Given quadratic equation is the general equation of a parabola having vertex at (h,k) is written as formulated in equation (1)
[tex]\rm y = a(x-h)^2 +k ............(1)[/tex]
where (h,k) is the vertex of the parabola
According to the given condition
Coordinates of vertex are
h = 1
k = 4
and also , the value of y intercept = 1
We have to determine the value of a in equation (1)
On putting the values of x, y, h and k in the equation (1) we get
[tex]\rm 1 = a(0-1)^2 + 4 \\a =-3[/tex]
So
The value of a if the quadratic function is written in the form
[tex]\rm y = a(x-h)^2 +k[/tex] given as follows
a = -3
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