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A ball of mass 0.5 kg is released from rest at a height of 30 m. How fast is it going when it hits the ground? Acceleration due to gravity is g = 9.8 m/s2.

Respuesta :

RickyChen
Assume you don't consider air friction.

Then mgh = 1/2 mv^2

v = sqrt(2gh) = sqrt(2*9.8 * 30) = 24.25 m/s

When a ball is released from rest, its initial velocity is zero. The velocity of the ball while hitting the ground is 24.25 m/s.

What is potential energy?

The potential energy is the energy stored in an object by virtue of its distance from the Earth's surface.

Mass of ball, m is 0.5 kg, height h achieved is 30 m and acceleration due to gravity g is 9.8 m/s².

At any point of motion, potential energy = kinetic energy

mgh = 1/2 mv²

v= √(2gh)

Substitute the values and solve for velocity while hitting the ground is

v =√(2 x 9.8 x 30)

v = 24.25 m/s

Thus, the velocity of the ball while hitting the ground is 24.25 m/s.

Learn more about potential energy.

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