First find the rate of growth using the formula of
A=p e^rt
A 7200
P 6000
E constant
R rate of growth?
T time 6 hours
We need to solve for r
R=[log (A/p)÷log (e)]÷t
R=(log(7,200÷6,000)÷log(e))÷6
R=0.03 rate of growth
Now predict how many bacteria will be present after 17 hours using the same formula
A=p e^rt
A ?
P 6000
R 0.03
E constant
T 17 hours
A=6,000×e^(0.03×17)
A=9,991.7 round your answer to get
A=9992
