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Using whichever equation you prefer (part a, b, or c), find the speed of light in meters per second if a mass of 3 kilograms converts to 2.7 × 1017 joules (J = )

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[tex]Given:\\m=3kg\\E=2.7\cdot 10^{17}J\\\\Find:\\c=?\\\\Solution:\\\\E=mc^2\\\\c^2= \frac{E}{m} \\\\c= \sqrt{\frac{E}{m}} \\\\c= \sqrt{ \frac{2.7\cdot 10^{17}J}{3} } = (2.7\cdot 10^{16} \frac{m^2}{s^2} )^{ \frac{1}{2} }=3\cdot 10^{8} \frac{m}{s}[/tex]

From Einstein's energy equation, the speed of light is calculated as; 3  * 10⁸ m/s

How to work with the energy equation?

We know that Einstein's energy equation is;

E = mc²

where;

E = energy

m = mass

c =  speed of light

We are given;

m = 3 kg

E = 2.7 * 10¹⁷ J

Thus;

2.7 * 10¹⁷ = 3c²

c = √(2.7 * 10¹⁷/3)

c = 3 * 10⁸ m/s

Read more about energy equation at; https://brainly.com/question/2772265

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