Please help, I really have absolutely no idea how to do this.

Final Answer-Explanation:
To find the solution to the given system of equations:
Equation 1: 5x + 5y = 20
Equation 2: -5x - y = -16
We can solve this system using the method of substitution or elimination. Let's use the method of elimination:
Step 1: Multiply equation 2 by 5 to make the coefficients of x in both equations equal:
5(-5x - y) = 5(-16)
-25x - 5y = -80
Step 2: Add equation 1 and equation 2 together:
(5x + 5y) + (-25x - 5y) = 20 + (-80)
5x - 25x + 5y - 5y = -60
Simplifying the equation:
-20x = -60
Divide both sides by -20:
x = 3
Step 3: Substitute the value of x back into one of the original equations (Equation 1 or Equation 2) to find the value of y. Let's use Equation 1:
5(3) + 5y = 20
15 + 5y = 20
Subtract 15 from both sides:
5y = 5
Divide both sides by 5:
y = 1
Therefore, the solution to the given system of equations is x = 3 and y = 1.
Answer:
(3,1)
Step-by-step explanation:
Using the elimination method, treat it like a simple subtraction problem as if "5x + 5y = 20" is the top number and "-5x - y = -16" as the bottom one and what you are subtracting.
First, get rid of the x so that you are left with only one variable.
(see attached work)
5x and - 5x cancel each other out.
Then 5y - y = 4y
and 20 - 16 = 4
Which leaves you with 4y = 4
Divide both sides by 4
y = 1
Then plug in y = 1 into the first equation
[tex]5x + 5(1) = 20\\5x + 5 = 20\\5x = 15\\x = 3[/tex]
Then write it as a coordinate point
(x,y) = (3,1)