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Final Answer-Explanation:

To find the solution to the given system of equations:

Equation 1: 5x + 5y = 20

Equation 2: -5x - y = -16

We can solve this system using the method of substitution or elimination. Let's use the method of elimination:

Step 1: Multiply equation 2 by 5 to make the coefficients of x in both equations equal:

5(-5x - y) = 5(-16)

-25x - 5y = -80

Step 2: Add equation 1 and equation 2 together:

(5x + 5y) + (-25x - 5y) = 20 + (-80)

5x - 25x + 5y - 5y = -60

Simplifying the equation:

-20x = -60

Divide both sides by -20:

x = 3

Step 3: Substitute the value of x back into one of the original equations (Equation 1 or Equation 2) to find the value of y. Let's use Equation 1:

5(3) + 5y = 20

15 + 5y = 20

Subtract 15 from both sides:

5y = 5

Divide both sides by 5:

y = 1

Therefore, the solution to the given system of equations is x = 3 and y = 1.

Answer:

(3,1)

Step-by-step explanation:

Using the elimination method, treat it like a simple subtraction problem as if "5x + 5y = 20" is the top number and "-5x - y = -16" as the bottom one and what you are subtracting.

First, get rid of the x so that you are left with only one variable.

(see attached work)

5x and - 5x cancel each other out.

Then 5y - y = 4y

and 20 - 16 = 4

Which leaves you with 4y = 4

Divide both sides by 4

y = 1

Then plug in y = 1 into the first equation

[tex]5x + 5(1) = 20\\5x + 5 = 20\\5x = 15\\x = 3[/tex]

Then write it as a coordinate point

(x,y) = (3,1)

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