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Suppose that E and F are points on the number line. If EF=12 and E lies at −4, where could F be located?
If there are several locations, separate them with commas.

Respuesta :

The distance between two points is defined as [tex]|A - B|[/tex]

We know that the distance between E and F is 12 units.
The point E is at the point -4.

I'll use X for the point F.

Now we have the equation [tex]|-4 - X| = 12[/tex]

Solve for X.

We have two possible equations: [tex]-4 - X= 12[/tex] and [tex]-4 - X = -12[/tex]

Solve each of them.

-4 - X = 12

Using the Addition Principle of Equality, we can add 4 to each side of the equation and will still get an equation with the same solution.

-4 - X + 4 = 12 + 4
X = 16

Now for the second equation.

-4 - X = -12

Just like with the equation above, we can use the Addition Principle of Equality to add 4 to each side of the equation and still get an equation with the same solution.

-4 - X + 4 = -12 + 4
-X = -8

-X = -8 is the same thing as X = 8 because we can divide both sides -1 to get X = 8.

So, the two points where X could be are the points -16 and 8.

We want to know the possible locations of F, given that we know the distance between E and F, and the location of E.

The two possible locations of F are: -16, 8.

We know that:

  • E is on -4
  • And EF = 12

This means that the distance between E and F is 12 units, and that the location of E is -4.

Then F can be 12 units below or 12 units above E.

If F is 12 units below E, to find the location of F we just take the location of E and subtract 12:

-4 - 12 = -16

One possible location of F is -16

The other possible location is given by adding 12 to the location of E:

-4 + 12 = 8

The other possible location of F is 8.

Then the two possible locations of F are: -16, 8.

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