You are given a process of 2SO₂(g) + O₂(g) → 2SO₃
(g) with ΔS = –187.9 J/K and ΔH = –198.4 kJ at 297.0 K. You are asked to find the entropy of this reaction. The entropy of this reaction is
ΔS = –187.9 J/K. ΔS stands for change in entropy and ΔH stands for change in enthalpy. It follows the second law of thermodynamics, the entropy in which all
things go into the chaotic state from a higher form into lower form. A chemical reaction
has an increase in entropy and a decrease in enthalpy. A chemical reaction is spontaneous if it has an entropy greater
than zero and an enthalpy less than 0. The chemical reaction given is spontaneous.
