Respuesta :
3x-7+c=x^2+4x-1
find c
minus 3x from both sides
-7+c=x^2+x-1
add 7 to both sides
c=x^2+x+6
x^2+x+6 must be added
find c
minus 3x from both sides
-7+c=x^2+x-1
add 7 to both sides
c=x^2+x+6
x^2+x+6 must be added
The term that can be added is the difference between the two expressions you have:
x^2+4x-1-(3x-7)
x^2+4x-1-3x+7
x^2+x+6
x^2+4x-1-(3x-7)
x^2+4x-1-3x+7
x^2+x+6