answer
Let's address each part of your question:
1. **Drawing the Bar Graph and Pictograph**:
- Bar Graph: We'll represent the number of students for each color choice using rectangular bars.
- Pictograph: We'll use symbols or pictures to represent the number of students for each color choice.
2. **Conversions**:
a) Convert \(30^\circ C\) to \(F\) using the formula \(F = \frac{9}{5}C + 32\).
b) Convert \(113^\circ F\) to \(C\) using the formula \(C = \frac{5}{9}(F - 32)\).
c) Convert \(36 \, \text{km/hr}\) to \(m/s\) by multiplying by \(\frac{5}{18}\) (since \(1 \, \text{km/hr} = \frac{5}{18} \, \text{m/s}\)).
d) Convert \(45 \, \text{m/s}\) to \(km/hr\) by multiplying by \(\frac{18}{5}\) (since \(1 \, \text{m/s} = \frac{18}{5} \, \text{km/hr}\)).
Let's proceed with each step:
### Bar Graph and Pictograph:
| Color Choice | Red | Blue | Green | Yellow | Orange |
|--------------|-----|------|-------|--------|--------|
| No. of Students | 16 | 36 | 8 | 24 | 20 |
Now, let's draw the bar graph and pictograph using this data.
### Conversions:
a) \(30^\circ C\) to \(F\):
\[F = \frac{9}{5}(30) + 32 = 54 + 32 = 86^\circ F\]
b) \(113^\circ F\) to \(C\):
\[C = \frac{5}{9}(113 - 32) = \frac{5}{9}(81) = 45^\circ C\]
c) \(36 \, \text{km/hr}\) to \(m/s\):
\[36 \, \text{km/hr} \times \frac{5}{18} = 10 \, \text{m/s}\]
d) \(45 \, \text{m/s}\) to \(km/hr\):
\[45 \, \text{m/s} \times \frac{18}{5} = 162 \, \text{km/hr}\]
These are the conversions for the given values.
Let me know if you need assistance with drawing the graphs or further clarification on conversions!
