maryoomsaggaf
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!!!!!!!!!!! 100 POINTS !!!!!!!!!!!!!!!!!!! ENSURE YOUR ANSWER IS CORRECT BEFORE POSTING !!!!!
(Past Paper Revision - the answer is enclosed)
How would you go about solving this? Please provide formulae, rules, explanation / working out . Thank you in advance!

100 POINTS ENSURE YOUR ANSWER IS CORRECT BEFORE POSTING Past Paper Revision the answer is enclosed How would you go about solving this Please provide formulae class=
100 POINTS ENSURE YOUR ANSWER IS CORRECT BEFORE POSTING Past Paper Revision the answer is enclosed How would you go about solving this Please provide formulae class=

Respuesta :

fieryanswererft

Answer:

[tex]\sf c= \dfrac{-(4g + 25)}{g+6}[/tex]

Explanation:

[tex]\sf g = \dfrac{c+3}{4+c}-7[/tex]

[tex]\sf g +7 = \dfrac{c+3}{4+c}[/tex]

[tex]\sf (g +7)(4+c) = {c+3}[/tex]

[tex]\sf 4g + gc + 28 + 7c = c + 3[/tex]

collect the variable c in one side

[tex]\sf gc + 7c-c = 3-4g-28[/tex]

[tex]\sf gc + 6c= -25-4g[/tex]

[tex]\sf c(g + 6)= -25-4g[/tex]

[tex]\sf c= \dfrac{-25-4g}{g+6}[/tex]

[tex]\sf c= \dfrac{-(25+4g)}{g+6}[/tex]

[tex]\sf c= \dfrac{-(4g + 25)}{g+6}[/tex]

semsee45

Answer:

[tex]c=\dfrac{-(4g+25)}{g+6}[/tex]

Step-by-step explanation:

Given equation:

[tex]g=\dfrac{c+3}{4+c}-7[/tex]

To make c the subject of the given equation, begin by adding 7 to both sides:

[tex]g+7=\dfrac{c+3}{4+c}[/tex]

Multiply both sides by (4 + c):

[tex](g+7)(4+c)=c+3[/tex]

Expand the left side:

[tex]4g+cg+28+7c=c+3[/tex]

Rearrange the equation so the terms in c are on the left side and the other terms are on the right side:

[tex]cg+7c-c=3-28-4g[/tex]

[tex]cg+6c=-4g-25[/tex]

Factor out c from the left side and factor out negative 1 from the right side:

[tex]c(g+6)=-(4g+25)[/tex]

Divide both sides by (g + 6):

[tex]c=\dfrac{-(4g+25)}{g+6}[/tex]

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