Respuesta :
First, we need to compute the mass of oxygen found in 100 grams of saltpeter:
mass of oxygen = 100 - (mass of potassium + mass of nitrogen)
= 100 - (38.67 + 13.86)
= 100 - 52.53
mass of oxygen in 100 grams saltpeter = 47.47 grams
Now, we can use cross multiplication to find the mass of oxygen in 328 grams saltpeter as follows:
mass of oxygen = (328 x 47.47) / 100 = 155.7016 grams
mass of oxygen = 100 - (mass of potassium + mass of nitrogen)
= 100 - (38.67 + 13.86)
= 100 - 52.53
mass of oxygen in 100 grams saltpeter = 47.47 grams
Now, we can use cross multiplication to find the mass of oxygen in 328 grams saltpeter as follows:
mass of oxygen = (328 x 47.47) / 100 = 155.7016 grams
Answer : The mass of oxygen contained is, 0.1557 gram
Solution : Given,
Mass of potassium = 38.67 g
Mass of nitrogen = 13.86 g
First we have to calculate the mass of oxygen contained.
Mass of oxygen contained = 100 - (Mass of potassium + Mass of nitrogen)
Mass of oxygen contained = 100 - (38.67 + 13.86) = 47.47 g
Now we have to calculate the mass of oxygen contained in 328.0 mg or 0.328 g.
(1 g = 1000 mg)
In 100 gram of water, the mass of oxygen contained = 47.47 g
In 0.328 gram of water, the mass of oxygen contained = [tex]\frac{47.47}{100}\times 0.328=0.1557g[/tex]
Therefore, the mass of oxygen contained is, 0.1557 gram